0=-16t^2+45t-8.8

Solution for 0=-16t^2+45t-8.8 equation:

0=-16t^2+45t-8.8

We move all terms to the left:

0-(-16t^2+45t-8.8)=0

We add all the numbers together, and all the variables

-(-16t^2+45t-8.8)=0

We get rid of parentheses

16t^2-45t+8.8=0

a = 16; b = -45; c = +8.8;
Δ = b2-4ac
Δ = -452-4·16·8.8
Δ = 1461.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{1461.8}}{2*16}=\frac{45-\sqrt{1461.8}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{1461.8}}{2*16}=\frac{45+\sqrt{1461.8}}{32}
$